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Mapúa Institute of Technology

Muralla St. Intramuros, Manila
School of Civil, Environmental, and Geological Engineering

Field Work No.1
Breaking the Tape Method
CE120-0F – B9

Submitted by:
Name: Gicale, Patrick Emmanuel T.

Student No: 2014106318

Group No: 4
Date of Performance: July 26, 2016
Date of Submission: August 2, 2016

Grade
Submitted to: Engr. Bienvenido Cervantes

also known as "Electronic Tape Measures". and the range poles are erect properly. nearly any object. and the device will show the distance on its LCD screen. By observing the two range poles on eye-level. the performers are required to find the area of the land in a shape of a polygon. Recommendation: Industrialization pave the way to advance technology. we solved the area of the polygon. our field work is a success as the performers were able to achieve the objectives of the field work. a utility pole. and chalk as a marker. and one of our member records the data gathered. offer true laser light (not sound) for the most accurate measuring. You simply point the laser distance measuring devices dot at a target like a wall. This resulted to the birth of new surveying equipment. Through the use of the 50 meter tape. I can conclude that all grounds are uneven. one of our member is the one who checks if our set-up is correct. In this field work activity. 2 range poles. a house. 1 demonstrates the basic way of determining an area of a field by the use of meter tape. by obtaining the length through the meter tape and solving the area by Heron's Formula.Discussion: Field work no. the meter tape doesn't sags. Relating it to our fieldwork. "Laser Distance Finders" or "Digital Measuring Devices". Fieldwork 1 introduces as the basic way of determining the horizontal distance. This simply tells us that there will be no even ground. modern way of determining the horizontal distance is through Laser Distance Measuring Tool. This fieldwork teaches us possible source of problems to develop our skills in determining the horizontal distance may it be the use of a tape or any advance surveying equipment. . we plot the five corners of our pentagon at the Intramuros Walls. it can be easily seen that one of the pole is higher than the other one even though the meter tape is set-up perpendicular to the pole. There will always be a point where the elevation differs to any point of the ground. Two of our members where task to hold the range poles and the other ends of the meter tape. So. specifically a pentagon. Laser Distance Measuring Tools. Conclusion: Objectively. After obtaining all the required data.

74 67.51 Method 3: Heron’s Formula Triangle 1 2 3 Sides a b c 10.3 m O 10.57 85.42 24.33O 13.06 10.8 26.9 Half Perimeter (S) Area 21.5 21.79 116.5 m B 108.8 12.72O 12.93 8. m) 67.4 61.3O 21.5 21.84 116.3 19.30 269.Final Data Sheet Sketch: C 8.79 116.32O 24.3 21.35 m 18.71 Area 67.30 85.30 .68 19.4 Total Area (sq.9 m 19.4 m Base and Altitude Method Height (m) 6.27 89.8 D O m 66.98O 61.30 269.32 24.3 10.42 85.92 Total Method 2: By two sides and the included angle Triangle 1 2 3 E Base (m) 19.4 21.3 12.3 18.3 m A Method 1: By Triangle 1 2 3 82.72 Sides (m) a b 13.3 21.3 Angle (θ in degrees) 108.6 13.5 8 21.4O 31.3 19.68 40.33O 35.5 8.

3 m) ( 10.m 2 2 1 1 A 2= bh= ( 21.32=67.68 m ) sin 108.42Asq3= . 1 1 A 1= bh= ( 19.4=85.42+85.51 Computations: A.84 +116.3 sq .72=116.5 1 s A 2= absin ∅= ( 19. 1 1 1 1 A 1= absin ∅= ( 13. m=269.3 ) sq .5m ) ( 6. m=269.4 m ) sin 61.3 m )( 12. m 2 2 2 2 1 1 A = A1 + A2 + A3 =( 67.3 m )( 10. m absin ∅= ( 21. m 2 2 A Total = A1 + A2 + A3 =( 67.3 ) sq .Total 269.92 m) =116.5 m )( 21.3 m ) sin 24.93 m )=67.57 sq .84 sq .3 m) ( 8.79 sq .m 2 2 1 1 A 3= bh= ( 21.79+116.71 sq B.06 m )=85. mTotal 2 2 .3 sq .57+85.

74−19.3−12.5 m =21.8−21.68 m+19.3 m+10.3)( 26. m A 3= √ s( s−a)( s−b)(s−c)= √ 26.3 m+18. m A Total = A1 + A2 + A3 =( 67. m .3 ) sq .4 m+ 21.8(24.3 m 2 A 1= √ s(s−a)(s−b)(s−c )=√ 21.9)=116.8−8.42+85.3)(24. m A 2= √ s(s−a)(s−b)(s−c )=√ 24.5)=67. m=269.8 m+19.5)=85.3)(21.74 m 2 S 2= S 1= 21.68)(21.8 m 2 12.8−19.8)(24.74(21.3(26.5 m =24.79 sq .C.3 m+8.79+116.4)(26. S 1= 13.3 sq .51 sq .3−21.74−10.42 sq .3−18.74−13.9 m =26.

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