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Mapúa Institute of Technology

Muralla St. Intramuros, Manila
School of Civil, Environmental, and Geological Engineering

Field Work No.1
Breaking the Tape Method
CE120-0F – B9

Submitted by:
Name: Gicale, Patrick Emmanuel T.

Student No: 2014106318

Group No: 4
Date of Performance: July 26, 2016
Date of Submission: August 2, 2016

Grade
Submitted to: Engr. Bienvenido Cervantes

There will always be a point where the elevation differs to any point of the ground. the performers are required to find the area of the land in a shape of a polygon. After obtaining all the required data. 2 range poles. Relating it to our fieldwork. one of our member is the one who checks if our set-up is correct. Laser Distance Measuring Tools. You simply point the laser distance measuring devices dot at a target like a wall. This fieldwork teaches us possible source of problems to develop our skills in determining the horizontal distance may it be the use of a tape or any advance surveying equipment. 1 demonstrates the basic way of determining an area of a field by the use of meter tape. a house. by obtaining the length through the meter tape and solving the area by Heron's Formula. This resulted to the birth of new surveying equipment. . we plot the five corners of our pentagon at the Intramuros Walls. we solved the area of the polygon. Recommendation: Industrialization pave the way to advance technology. and the range poles are erect properly. In this field work activity. it can be easily seen that one of the pole is higher than the other one even though the meter tape is set-up perpendicular to the pole. "Laser Distance Finders" or "Digital Measuring Devices". modern way of determining the horizontal distance is through Laser Distance Measuring Tool. I can conclude that all grounds are uneven. By observing the two range poles on eye-level. Through the use of the 50 meter tape.Discussion: Field work no. the meter tape doesn't sags. So. offer true laser light (not sound) for the most accurate measuring. Fieldwork 1 introduces as the basic way of determining the horizontal distance. nearly any object. and the device will show the distance on its LCD screen. specifically a pentagon. our field work is a success as the performers were able to achieve the objectives of the field work. and chalk as a marker. Conclusion: Objectively. a utility pole. also known as "Electronic Tape Measures". This simply tells us that there will be no even ground. Two of our members where task to hold the range poles and the other ends of the meter tape. and one of our member records the data gathered.

5 8 21.74 67.5 8.42 85.51 Method 3: Heron’s Formula Triangle 1 2 3 Sides a b c 10.4 Total Area (sq.4 21.71 Area 67.35 m 18.3 m A Method 1: By Triangle 1 2 3 82.9 Half Perimeter (S) Area 21.3 19.5 21.30 85.30 269.3 12.3O 21.8 26.3 m O 10.33O 35.98O 61.5 m B 108.3 19.84 116.27 89.06 10.57 85.9 m 19.4 61.4 m Base and Altitude Method Height (m) 6.3 Angle (θ in degrees) 108.92 Total Method 2: By two sides and the included angle Triangle 1 2 3 E Base (m) 19.72O 12.68 40.93 8.3 21.3 21.Final Data Sheet Sketch: C 8.30 269.30 . m) 67.6 13.8 12.33O 13.5 21.32 24.8 D O m 66.3 18.68 19.42 24.72 Sides (m) a b 13.32O 24.4O 31.3 10.79 116.79 116.

51 Computations: A.3 m ) sin 24. m 2 2 A Total = A1 + A2 + A3 =( 67.3 m) ( 8.57 sq .93 m )=67. mTotal 2 2 .4=85.84 +116. 1 1 A 1= bh= ( 19.3 m) ( 10.32=67. m absin ∅= ( 21.71 sq B. 1 1 1 1 A 1= absin ∅= ( 13.Total 269.3 m )( 12.57+85.79 sq .06 m )=85.42Asq3= .m 2 2 1 1 A 2= bh= ( 21.3 sq . m 2 2 2 2 1 1 A = A1 + A2 + A3 =( 67. m=269.72=116.m 2 2 1 1 A 3= bh= ( 21.5 1 s A 2= absin ∅= ( 19.42+85.5m ) ( 6.4 m ) sin 61.68 m ) sin 108. m=269.79+116.3 ) sq .3 sq .3 ) sq .5 m )( 21.92 m) =116.84 sq .3 m )( 10.

3−18.42 sq .8 m+19.9 m =26. m A 2= √ s(s−a)(s−b)(s−c )=√ 24.8(24.3−12.3)( 26. m A 3= √ s( s−a)( s−b)(s−c)= √ 26.9)=116.42+85.8)(24.5)=67.3 ) sq .3−21. m A Total = A1 + A2 + A3 =( 67.8−19.68 m+19.3 m+10.68)(21.79 sq .74(21.8−21.3)(24.3 m 2 A 1= √ s(s−a)(s−b)(s−c )=√ 21.51 sq .74−10.4)(26.5 m =24.5)=85.3 m+18.74−13.79+116.8−8.3(26.3)(21.5 m =21. m=269. S 1= 13.4 m+ 21.3 m+8. m .74 m 2 S 2= S 1= 21.8 m 2 12.3 sq .74−19.C.

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