Mapúa Institute of Technology

Muralla St. Intramuros, Manila
School of Civil, Environmental, and Geological Engineering

Field Work No.1
Breaking the Tape Method
CE120-0F – B9

Submitted by:
Name: Gicale, Patrick Emmanuel T.

Student No: 2014106318

Group No: 4
Date of Performance: July 26, 2016
Date of Submission: August 2, 2016

Grade
Submitted to: Engr. Bienvenido Cervantes

This fieldwork teaches us possible source of problems to develop our skills in determining the horizontal distance may it be the use of a tape or any advance surveying equipment. There will always be a point where the elevation differs to any point of the ground. by obtaining the length through the meter tape and solving the area by Heron's Formula. and one of our member records the data gathered. and the device will show the distance on its LCD screen. You simply point the laser distance measuring devices dot at a target like a wall. one of our member is the one who checks if our set-up is correct. it can be easily seen that one of the pole is higher than the other one even though the meter tape is set-up perpendicular to the pole. This resulted to the birth of new surveying equipment. After obtaining all the required data. By observing the two range poles on eye-level.Discussion: Field work no. our field work is a success as the performers were able to achieve the objectives of the field work. nearly any object. we plot the five corners of our pentagon at the Intramuros Walls. modern way of determining the horizontal distance is through Laser Distance Measuring Tool. "Laser Distance Finders" or "Digital Measuring Devices". Through the use of the 50 meter tape. Relating it to our fieldwork. specifically a pentagon. Recommendation: Industrialization pave the way to advance technology. the performers are required to find the area of the land in a shape of a polygon. and chalk as a marker. Conclusion: Objectively. and the range poles are erect properly. also known as "Electronic Tape Measures". Two of our members where task to hold the range poles and the other ends of the meter tape. This simply tells us that there will be no even ground. . we solved the area of the polygon. a house. the meter tape doesn't sags. a utility pole. In this field work activity. offer true laser light (not sound) for the most accurate measuring. So. Laser Distance Measuring Tools. 1 demonstrates the basic way of determining an area of a field by the use of meter tape. I can conclude that all grounds are uneven. 2 range poles. Fieldwork 1 introduces as the basic way of determining the horizontal distance.

79 116. m) 67.Final Data Sheet Sketch: C 8.93 8.30 269.74 67.8 26.84 116.32O 24.92 Total Method 2: By two sides and the included angle Triangle 1 2 3 E Base (m) 19.27 89.71 Area 67.3 Angle (θ in degrees) 108.3 10.4 Total Area (sq.9 Half Perimeter (S) Area 21.5 8.72 Sides (m) a b 13.5 m B 108.68 19.4 61.4O 31.5 21.9 m 19.98O 61.33O 13.8 D O m 66.06 10.4 21.3 19.72O 12.3 m A Method 1: By Triangle 1 2 3 82.32 24.33O 35.3 19.68 40.79 116.57 85.3 21.8 12.42 85.30 269.6 13.5 8 21.3 21.4 m Base and Altitude Method Height (m) 6.3O 21.3 m O 10.3 12.5 21.35 m 18.42 24.51 Method 3: Heron’s Formula Triangle 1 2 3 Sides a b c 10.3 18.30 .30 85.

84 sq .71 sq B.68 m ) sin 108.5m ) ( 6.32=67.3 ) sq .3 m )( 10. m 2 2 A Total = A1 + A2 + A3 =( 67.57+85.4=85.3 sq .93 m )=67. m absin ∅= ( 21.5 1 s A 2= absin ∅= ( 19.3 m ) sin 24.3 m) ( 8.72=116. mTotal 2 2 .57 sq .51 Computations: A. m 2 2 2 2 1 1 A = A1 + A2 + A3 =( 67.3 ) sq .m 2 2 1 1 A 2= bh= ( 21.79 sq . m=269.Total 269.79+116.4 m ) sin 61.42Asq3= .84 +116.3 m) ( 10.92 m) =116.06 m )=85. m=269.42+85. 1 1 1 1 A 1= absin ∅= ( 13.3 m )( 12.5 m )( 21.m 2 2 1 1 A 3= bh= ( 21. 1 1 A 1= bh= ( 19.3 sq .

5 m =24. m A 2= √ s(s−a)(s−b)(s−c )=√ 24.79+116.3 m+18.3−12.3 m+8.3−18.8−8. m A 3= √ s( s−a)( s−b)(s−c)= √ 26.8 m+19.68)(21.74−10.42+85. m=269.8 m 2 12. m A Total = A1 + A2 + A3 =( 67.74−13. m .74−19.68 m+19.3 sq .9 m =26.3 ) sq .74 m 2 S 2= S 1= 21.8−19.42 sq .5)=85.5 m =21.8)(24.8−21.8(24.3)( 26.51 sq .9)=116.3(26.3)(24. S 1= 13.3)(21.4 m+ 21.3 m+10.4)(26.C.74(21.3 m 2 A 1= √ s(s−a)(s−b)(s−c )=√ 21.79 sq .5)=67.3−21.

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